Repository navigation
Read an exponential of an inverse below the bar as a negative multiple - #1935
Merged
Rafael-SOWNet merged 3 commits intoOct 18, 2026
Merged
Rafael-SOWNet merged 3 commits into
Rafael-SOWNet merged 3 commits into
Conversation
x^2/(e^(i arctan(a x)) (c + a^2 c x^2)^(3/2)) wrote the exponential as (1 + i a x)/sqrt(1 + a^2 x^2) below the bar, a linear with i in it the rational rules do not read there. Taken above the bar with its exponent negated, a negative whole multiple is written over the conjugate, (1 - i L)^(-n) (1 + L^2)^(n/2): x^2 (1 - i a x)/(c^(3/2) (1 + a^2 x^2)^2), which is answered (Rubi's 5.3.6:513). Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…le-of-the-arctangents-quadratic-splits
Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Add this suggestion to a batch that can be applied as a single commit.This suggestion is invalid because no changes were made to the code.Suggestions cannot be applied while the pull request is closed.Suggestions cannot be applied while viewing a subset of changes.Only one suggestion per line can be applied in a batch.Add this suggestion to a batch that can be applied as a single commit.Applying suggestions on deleted lines is not supported.You must change the existing code in this line in order to create a valid suggestion.Outdated suggestions cannot be applied.This suggestion has been applied or marked resolved.Suggestions cannot be applied from pending reviews.Suggestions cannot be applied on multi-line comments.Suggestions cannot be applied while the pull request is queued to merge.Suggestion cannot be applied right now. Please check back later.
x^2/(e^(i arctan(a x)) (c + a² c x²)^(3/2))was left unevaluated:SolveByWritingAnExponentialOfAnInverseAlgebraicallyread the exponential below the bar asn = 1. A pre-pass now takes an exponential of an inverse from below the bar to above it with its exponent negated. For a negative wholen,e^(n i arctan(L))is written over the conjugate,(1 - i L)^(-n) (1 + L²)^(n/2), so the linear withiin it is above the bar, where the rational rules read it.Part of #718 — Rubi's 5.3.6:513 and :515, and the
xand1siblings of :513. Master ran past the 5-second corpus budget on :515; it is answered in 110 ms.Measured against master b2ef509:
tanh(a + 2 ln x)^2/x^3and 3.5:37. They are Take a linear factor common to a sum below the bar out of it #1932's (the branch's base included it and the master arm did not), and they give the same result on Take a linear factor common to a sum below the bar out of it #1932's own build;After merging master 2bc0561 (which brings #1934's rule for the same exponentials): built for every target, suite 15,561 passed, and the pocket again, 317/325 with 0 wrong. The only change from the branch alone is #1934's two gains.
Recorded in BREAKING-CHANGES.md.
🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura